Prove that if m^2 - n^2 is even, then m - n is even also.

Step-by-step explanation:

Given

is even i.e.

it is a multiple of 2

let us suppose it 2k

and we know that it is possible only when either both m&n is odd or even

i.e.

=even number

=odd number

thus m-n is even for both case i.e. for both m&n either odd or even

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.