Question 7 10 points save answer you are spinning a 025 kg mass over your head at the end of a 0 5 m string lif you let go of the string the mass wil sail ofof a tangent at 2 mis what isthe angular momenturm of the spining mass belore you are spinning a 0 25 kg mass over your head at the release? because angular momentum is always conserved, where does the angular momentum go atter release? question 8 10 points save answer

angular moment is 0.25 kg.m²/s

Step-by-step explanation:

given data in question

mass (m) = 0.25 kg

length of string i.e. radius (r) = 0.5 m

velocity = 2 m/s

to find out

angular momentum before mass release

solution

we know angular moment formula i.e.

angular moment = mass × velocity × radius   1

put the value mass velocity and radius in equation 1 we get angular moment i.e.

angular moment = mass × velocity × radius

angular moment = 0.25 × 2 × 0.5

angular moment = 0.25

so the angular moment is 0.25 kg.m²/s before release and 0.25 kg.m²/s after release because angular momentum is always conserved

you would have to sell 24 bracelets.

step-by-step explanation:

84/3.5 = 24

all the angles opposite to the angle 150 would be 150 and all the angles that are next to 150 are 30 because they equal 180 it you add it up.

step-by-step explanation: