How long is the second hand to the nearest tenth if it moves 2cm in 15 seconds?

let's recall that a circular clock has 360° and 60 seconds per minute.

the seconds hand does 60 seconds in one go-around, and if it has covered 15 seconds on the clock, that gives us an angle of 90°, 15 is one quarter of 60, so in 15 seconds it has covered one quarter of the full circle or 90°.

we also know it covered 2cm, namely the arc's length on the 15 seconds is 2cm.

on a coordinate grid, point a is at (−4.0, −2.4) and point b is at (4.0, −2.4). point b is a reflection of point a across the –axis. input either a lowercase x or i think is the right awnser

step-by-step explanation: