Consider the vectors u < -4,7> and v= < 11,-6>
see picture for more information.

u + v = <7 , 1>

║u + v║ ≅ 7

Step-by-step explanation:

* Lets explain how to solve the problem

- We can add two vector by adding their parts

∵ The vector u is <-4 , 7>

∵ The vector v is <11, -6>

∴ The sum of u and v = <-4 , 7> + <11 , -6>

∴ u + v = <-4 + 11 , 7 + -6> = <7 , 1>

∴ The sum u and v is <7 , 1>

* u + v = <7 , 1>

- The magnitude of the resultant vector = √(x² + y²)

∵ x = 7 and y = 1

∵ ║u + v║ means the magnitude of the sum

∴ The magnitude of the resultant vector = √(7² + 1²)

∴ The magnitude of the resultant vector = √(49 + 1) = √50

∴ The magnitude of the resultant vector = √50 = 7.071

* ║u + v║ ≅ 7

x is variable or an unknown value to find

example:

2x = 5 which means x = 3

answer: option a.

step-by-step explanation:

you know that the quadrilateral opqr ( a four sided figure) is inscribed in circle. this means that all its vertices are on the circle.

then, by definition, the opposite angles of the quadrilateral are supplementary, this means that the sum of their measures is 180 degrees.

you can observe in the figure that the angles ∠opq   and the angle ∠orq   are opposite, therefore:

then, can be used to d to calculate the measure of ∠opq