One solution of 10x^2 + bx – 3 = 0 is - 4/5 find b and the other solution.
what is the value of b in the equation?

see explanation

Step-by-step explanation:

Given that x = - is a solution of the equation

Then substitute this value into the equation and solve for b

10 ( - )² + b(- ) - 3 = 0

10 × - b - 3 = 0

- b - 3 = 0

Multiply through by 5

32 - 4b - 15 = 0

17 - 4b = 0 ( subtract 17 from both sides )

- 4b = - 17 ( divide both sides by - 4 )

b = ← value of b

Given α and β are the roots of a quadratic equation, then

α + β = -

let α = - , then with a = 10 and b = b

- + β = - = -

β = - + =

Hence the other solution is x =

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