Aresearcher is interested in estimating the mean weight of a semi trailer truck to determine the potential load capacity. she takes a random sample of 17 trucks and computes a sample mean of 20,000 pounds with sample standard deviation of 1,500. the 95% confidence interval for the population mean weight of a semi trailer truck is

95% confidence interval = 20,000 ± 2.12

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

Step-by-step explanation:

Given :

Sample size(n) = 17

Sample mean = 20000

Sample standard deviation = 1,500

5% confidence

∴ = 0.025

Degree of freedom () = n-1 = 16

∵ Critical value at ( 0.025 , 16 ) = 2.12

∴ 95% confidence interval = mean ±

Critical value  at 95% confidence interval = 20,000 ± 2.12

( 19228.736 , 20771.263 ) OR ( 19229 , 20771 )

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet