An inspector samples four pc’s from a steady stream of computers that is known to be 12% nonconforming. what is the probability of selecting two nonconforming units in the sample? write your answer to 3 decimal places in the format: x. xxx

0.067

Step-by-step explanation:

Binomial distribution formula :-

, here P(x) is the probability of getting success in x trials , n is total number of trials and p is the probability of getting success in each trial.

Given : n = 4 , p = 12 % = 0.12 and x =2

Then ,

∴ The probability of selecting two nonconforming units in the sample = 0.067

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3