Sum of first nth term of the seris 2^2+4^2+6^2+8^2+ terms is

(2/3)n(n+1)(2n+1)

Step-by-step explanation:

First you have to find the general term formula which is here (2k)^2 which is equal to 4k^2. Sum(k=1 to n) of 4k^2=4•n(n+1)(2n+1)/6

simplified to (2/3)n(n+1)(2n+1)

answer: no, but if it does it's a obvious pattern.

step-by-step explanation:

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation: