Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for several seconds. the player began counting at 0 seconds, even though the video had already played 190 frames. the video plays 25 frames per second. how many frames had the video already played when the time was equal to -3 2/5 seconds?

105 frames

Step-by-step explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames.

The number of frames when the time was equal to seconds is 125.

Step-by-step explanation:

It is given that the player began counting at 0 seconds, even though the video had already played 190 frames. The video plays 25 frames per second.

The slope intercept form of linear function is

where, m is rate of change and b is initial value.

It means the initial number of frames = 190

Change in frames per second = 25

The equation that represents the number of frames after x seconds is

           .... (1)

We need to find the number of frames when the time was equal to seconds.

Substitute in equation (1),

Therefore the number of frames when the time was equal to seconds is 125.

yep

step-by-step explanation:

we can't see all full 4 options, but if this is the full option, than the very left one is correct:

-2/5 * -3 3/4

remake the question, adding a picture of all the question, or write down the full left and right answers.