Which of the following would be the most logical first step to solving this
quadratic equation?
2x2-x+ 2 = -11
o
a. divide both sides by x.
o
b. take the square root of both sides.
o
c. set up smaller equations using the zero product rule.
o
d. add 11 to both sides.

D is correct option

Step-by-step explanation:

The correct option is D.

The standard quadratic equation is ax²+bx+c=0

Where a and b are coefficients and c is constant.

It means that constant are on the L.H.S and there is 0 on the right hand side.

Therefore to make it a quadratic equation first of all you have to add 11 at both sides so that the R.H.S becomes 0.

The given equation is:

2x2-x+ 2 = -11

If we add 11 on both sides the equation will be:

2x2-x+ 2 +11= -11+11

2x^2-x+13=0

Thus the correct option is D

You can further solve it by applying quadratic formula

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!