Aresearcher wishes to estimate the proportion of adults who have high speed internet access. what size sample should be obtained if she wishes the estimate to be within 0.04 with 90% confidence if she uses a previous estimate of 0.54

421

Step-by-step explanation:

Margin of error = E = 0.04

Confidence Level = 90%

z value associated with this confidence level = z = 1.645

Previous estimate of population proportion = p = 0.54

q = 1 - p = 1 - 0.54 = 0.46

The formula of Margin of Error for population proportion is:

Here, n is the sample size.

Re-arranging the equation for n and using the values we get:

Thus the minimum sample size required to estimate the proportion of adults who have high speed internet access is 421

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.