If sin(theta) = -1/2, and pi < theta < 3pi/2, what is cos(theta)?

Step-by-step explanation:

If is between and

, then we are in third quadrant. This is where x (cosine value) and y (sine value) are both negative.

We are going to use a Pythagorean Identity, namely .

We are going to plug -1/2 for .

That gives us this equation to solve for :

Subtract 1/4 on both sides:

Square root both sides:

We already determine cosine value was negative.

i cant see the graph

step-by-step explanation: