Meredith bought 4 t-shirts and 2 pairs of pants. if x is the cost of one t-shirt and y is the cost of one pair of pants, she’ll have to multiply the number of t-shirts by x and the number of pants by y to find the total cost of the clothes.
write an expression for finding the total cost of the clothes?
apply the properties of operations to find an equivalent expression for finding the total cost of the clothes?
write an expression for finding the total cost of the clothes if meredith bought 6 t-shirts and 4 pairs of pants. also write an equivalent expression for that expression?

The total cost = 4x + 2y

The total cost = 2y + 4x

The total cost = 6x + 4y

The total cost = 4y + 6x

Step-by-step explanation:

* Lets explain how to solve the problem

- Meredith bought 4 T-shirts and 2 pairs of pants

∴ The number of T-shirts is 4

∴ The number of pairs of pants is 2

- x is the cost of one T-shirt and y is the cost of one pair of pants

∴ The cost of each T-shirt is x

∴ The cost of each pair pf pants is y

∵ The total cost is the sum of the products of the number of T-shirts

   and the cost of each one and the number of pair of pants and the

   cost of each one

∴ The total cost = (4 × x) + (2 × y)

∴ The total cost = 4x + 2y

- To find the equivalent expression switch the places of x and y

∴ The total cost = 2y + 4x

- Meredith bought 6 T-shirts and 4 pairs of pants

∴ The number of T-shirts is 6

∴ The number of pairs of pants is 4

∴ The total cost = (6 × x) + (4 × y)

∴ The total cost = 6x + 4y

- To find the equivalent expression switch the places of x and y

∴ The total cost = 4y + 6x

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.