What are the zeros of ax) = x2 - 12x + 36?
o a. x= -6 and x = 6
o b. x=-6 only
o c. x = 6 only
o d. x=-4 and x = 9
submit

The correct option is C

Step-by-step explanation:

x2 - 12x + 36

The coefficient of 1st term will be multiplied by the constant:

1*36 = 36

Now find two numbers whose product is 36 and whose addition is 12.

6*6 = 36

6+6 =12

Now break the middle term:

x^2-6x-6x+36 = 0

Now group the terms:

(x^2-6x) - (6x-36) = 0

Now take common of each group:

x(x-6)-6(x-6) = 0

(x-6) (x-6) =0

(x-6)=0    ,  (x-6) =0

x-6=0       , x-6=0

x=0+6      , x=0+6

x=6        ,   x=6

Thus the correct option is C. x=6 only

its ok i have one too and i also have big lips

step-by-step explanation: