For the function f(x) = -2(x + 3)2 - 1, identify the vertex, domain, and range
the vertex is (3,-1), the domain is all real numbers, and the range is y2-1
the vertex is (3,-1), the domain is all real numbers, and the range isys-t.
o the vertex is (-3, -1), the domain is all real numbers, and the range is ys-1
the vertex is (-3, -1), the domain is all real numbers and the range isy 2-1

The vertex is (-3, -1), the domain is all real numbers and the range is y ≤ -1.

Step-by-step explanation:

The general vertex form is f(x) = a(x - b)^2 + c where the vertex is (b, c).

So for f(x) = -2(x + 3)^2 - 1   the vertex is (-3, -1).

Because of the negative  coefficient of x^2 ( -2) the parabola opens downwards and the maximum value is -1. So the range is y ≤ -1.

The domain is all real numbers.

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6