Aprogrammer plans to develop a new software system. in planning for the operating system that he will​ use, he needs to estimate the percentage of computers that use a new operating system. how many computers must be surveyed in order to be 95% confident that his estimate is in error by no more than four percentage points question marks? assume that nothing is known about the percentage of computers with new operating systems.

n = 601

Step-by-step explanation:

Since we know nothing about the percentage of computers with new operating system, we assume than 50% of the computers have new operating system.

So, p = 50% = 0.5

q = 1 - p = 1 - 0.5 = 0.5

Margin of error = E = 4 percentage points = 0.04

Confidence Level = 95%

z value associated with this confidence level = z = 1.96

We need to find the minimum sample size i.e. n

The formula for margin of error for the population proportion is:

Re-arranging the equation for n, and using the values we get:

Thus, the minimum number of computers that must be surveyed is 601