Agraphed line shown shows y=5x-10
which equation, when graphed with the given equation, will form a system that has no solution?
a. y= -5x+10
b. y = 5(x+2)
c. y = 5(x-2)
d. y = -5x-10

Option B. y = 5(x+2)

Step-by-step explanation:

we have

y=5x-10

The slope of the given line is m=5

Remember that

If two lines are parallel, then their slopes are the same

If a system of linear equations has no solutions, then the lines of the system must be parallel lines with different y-intercept

Verify each case

case A) y=-5x+10

The slope of this line is m=-5

The slopes are different

therefore

This equation, when graphed with the given equation, will form a system that has one solution

case B) y=5(x+2)

y=5x+10

The slope of this equation is the same of the given equation and their y-intercepts are different

therefore

The system has no solutions

case C) y=5(x-2)

y=5x-10

This equation is the same of the given equation

therefore

The system has infinitely solutions

case D) y=-5x-10

The slope of this line is m=-5

The slopes are different

therefore

This equation, when graphed with the given equation, will form a system that has one solution

well if he bought them at 5 cedis each sold them at 7 cedis each then he would make a profit of 2 cedis of each book. if in total he made 150 cedis profit that means he sold 75 books. he lost 12 books at the start so that means he originally bought a total of 82 books.

step-by-step explanation:

multiplication is multiplication.   it might feel harder depending on what level of math you are in, but generally it will be the same old stuff, while implementing some new concepts and methods of solving work.