In the computer game world of warcraft, some of the strikes are critical strikes, which do more damage. assume that the probability of a critical strike is the same for every attack, and that attacks are independent. during a particular fight, a character has 251 critical strikes out of 591 attacks. what is the lower bound for the 99% confidence interval for the proportion of strikes that are critical strikes.

0.372

Step-by-step explanation:

Total number of attacks = n = 591

Number of critical strikes = x = 251

Proportion of critical strikes = p =

Proportion of non-critical strikes = q = 1 - p =

Confidence Level = 99%

Z-score for this confidence level = 2.58

The Lower bound for the population proportion is given by:

Using the values, we get:

The lower bound for the 99% confidence interval for the proportion of strikes that are critical strikes is 0.372

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb

answer is:

1.75 pounds