3x^2-2x-5
subject is factoring quadratic trinomials when a doesn’t =1

(x + 1)(3x - 5)

Step-by-step explanation:

Given

3x² - 2x - 5

To factor the quadratic

Consider the factors of the coefficient of the x² term and the constant term which sum to give the coefficient of the x- term

product = 3 × - 5 = - 15 and sum = - 2

The required factors are - 5 and + 3

Use these factors to split the x- term

3x² + 3x - 5x - 5 ( factor the first/second and third/fourth terms )

= 3x(x + 1) - 5(x + 1) ← factor out (x + 1) from each term

= (x + 1)(3x - 5) ← in factored form

i dont know

step-by-step explanation:

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