Let f(x)=x + 1 and g(x)=x2-x. find and simplify the expression.
(f+g)(2)

5

Step-by-step explanation:

(f+g)(2) means f(2)+g(2).

f(2) means to evaluate the expression called f at x=2.

So f is x+1 and it wants us to plug in 2 for x.

x+1 with x=2

2+1

3

This means f(2)=3, f(2) has value 3.

g(2) means to evaluate the expression called g at x=2.

So g is x^2-x and it wants us to plug in 2 for x.

x^2-x with x=2

2^2-2

4-2

2

This means g(2)=2, g(2) has value 2.

Let's go back to (f+g)(2).

(f+g)(2)=f(2)+g(2)

(f+g)(2)= 3  +   2        (I replaced f(2) with 3 and g(2) with 2).

(f+g)(2)=5

62.5 paisa

step-by-step explanation:

4000*70 = 280000

280000-(2000*90) = 100000

4000-2400 = 1600

100000/1600 = 62.5

( give brainliest)

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!