Amechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt. the chance that the dart thrower hits the bullseye at least once in 6 attempts is:

The probability of hitting the bullseye at least once in 6 attempts is 0.469.

Step-by-step explanation:

It is given that a mechanical dart thrower throws darts independently each time, with probability 10% of hitting the bullseye in each attempt.

The probability of hitting bullseye in each attempt, p = 0.10

The probability of not hitting bullseye in each attempt, q = 1-p = 1-0.10 = 0.90

Let x be the event of  hitting the bullseye.

We need to find the probability of hitting the bullseye at least once in 6 attempts.

      .... (1)

According to binomial expression

where, n is total attempts, r is number of outcomes, p is probability of success and q is probability of failure.

The probability that the dart thrower not hits the bullseye in 6 attempts is

Substitute the value of P(x=0) in (1).

Therefore the probability of hitting the bullseye at least once in 6 attempts is 0.469.

the answer is a

step-by-step explanation: