what is the number of ways to arrange 8 objects from a set of 12 different
objects?

19958400 ways

Step-by-step explanation:

As the question involves arrangement, permutation will be used.

P(n,r) = n! / (n-r)!

Here

n=12

and

r = 8

So,

P(12,8) = 12!/(12-8)!

= 12!/ 4!

=19958400 ways

Therefore, the 8 objects from 12 can be arranged in 19958400 ways ..

answer: about 22.67

step-by-step explanation:

given the equation is 8+9z=-6, the first step would be to subtract the 8 from both sides:

8+9z-8=-6-8

since 8 minus 8 = 0, this would cancel out the 8. and since -6 minus 8 equals -14, the equation would look like this

9z = -14