Part g
for the safety of the audience, the fireworks should be set to explode at least 450 feet above the ground. the length of the second fuse in a mortar firework controls when the firework explodes. the fireworks company has these four fuses available:
fuse a: the firework will explode in 1 to 3 seconds.
fuse b: the firework will explode in 3 to 5 seconds.
fuse c: the firework will explode in 6 to 8 seconds.
fuse d: the firework will explode in 8 to 10 seconds.
which fuse should the company use for your fireworks display, and why?

answer: 5100 just subtract

step-by-step explanation:

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

let's call the solutions x₁ = (5 - 2√7)/3 and x₂ = (5 + 2√7)/3

then the equation is (x-x₁)(x-x₂) = 0

if you fill that in you get a lot of numbers which you can recognize as ax²+bx+c=0.

step-by-step explanation:

you can see that a=1 (there is just an x²)

b = (-5 -2√7 + 2√7 - 5)/3 = -10/3

c = -2√7)/3 ) * (-5+2√7)/3) = -1/3

so your answer is 3x^2 – 10x – 1 = 0

answer: 5 17/33 % (to the tenth)

step-by-step explanation:

he guessed: 34.5 pounds

actual weight is 32.7

there for he is off:

34.5 -32.7 = 1.8

32.7 is the 100%

1.8 represents %? of 32.7

therefore:

32.7   - 100%

1.8     -     x%

x= 1.8*100%/32.7% = 18*100%/327%

x=1800%/327%   = (5 165/327)%

to the tenth:

5 17/33 %