If a+ b + c= -6 and x +y = 5, what is 9y +9x - 10a-10c -10b ?

9y +9x - 10a-10c -10b = 105

Step-by-step explanation:

Given

a+b+c = -6 and x+y = 5

We have to find 9y +9x - 10a-10c -10b

Rearranging the terms

9x+9y-10a-10b-10c

Simplifying will give us:

= 9 (x+y) - 10(a+b+c)

Putting the values of x+y and a+b+c

= 9(5) -10(-6)

=45+60

=105

Therefore,

9y +9x - 10a-10c -10b = 105 ..

9y + 9x - 10a - 10c - 10b  = 105

Step-by-step explanation:

It is given that,  a+ b + c = - 6 and x + y = 5

To find the value of given expression

Let the expression be 9y +9x - 10a-10c -10b

9y +9x - 10a -10c -10b  = 9(y + x) - 10(a + c + b )

 = 9(x + y) - 10(a + b + c)

 = 9 * (5) - 10 * (-6)

 = 45 + 60

 = 105

Therefore 9y + 9x - 10a - 10c - 10b  = 105

guess at question:

a vertical line intersects the graph of g(x,y) = 0 at two points. what conclusion follows about the function f(x) implicitly defined by g(x,f(x)) = 0?

the domain of f(x) cannot include the x coordinate of any such vertical line.

informally, f(x) is not a function, and

g(x,y)=0 cannot be solved for y uniquely.

the relation r = {(x,y) such that g(x,y) = 0} is a function if

for all (a,b) ∊ r and (c,d) ∊ r, a=c implies b=d.

step-by-step explanation: