If f(x)= x/3-2then find g(x) =3x^2+2x-6

Step-by-step explanation:

(f+g)(x)=3x^2+\frac{7}{3}x-8  

Step-by-step explanation:

The given functions are:

f(x)=\frac{x}{3}-2 and g(x)=3x^2+2x-6

Now, (f+g)(x)=f(x)+g(x)

therefore, (f+g)(x)=\frac{x}{3}-2+3x^2+2x-6

=3x^2+2x+\frac{x}{3}-8

=\frac{9x^2+6x+x-24}{3}

=\frac{9x^2+7x-24}{3}

=3x^2+\frac{7}{3}x-8

Thus, (f+g)(x)=3x^2+\frac{7}{3}x-8

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step-by-step explanation: