Figure ghjk is equivalent to a rectangle with a semicircle removed from both its top side and its bottom side. what is the area of figure ghjk? a. ( – ) ft2 b. ( – ) ft2 c. ( – ) ft2 d. ( – ) ft2

Okay, First, Lets Remember The Formulas. Area Of A Rectangle : 
B*H. 
Area Of A Circle:
R*2*3.14. 
16*12 Is The Area Of The Rectangle. 16*12 = 192.
Area Of The Two Semicircles = 6*6*3.14. 6*6 = 36. 36*3.14 =113.04. 
Now, 192-113.04 = 78.96 in ^2. Hope This Helps!

What MathGeek said was pretty correct except for the area of the circle.
The area of a circle is pi r squared, aka pi*radius to the second power.

So, it should be 192 - 36pi ( the radius would be 6, because radius is half the diameter, and 6 to the second power is 36 ).

:D You're welcome.

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3