The equation of line wx is 2x+y=-5. what is the equation of a line perpendicular to line wx in slope-intercept form that contains point (-1,-2)?

see explanation

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2x + y = - 5 into this form by subtracting 2x from both sides

y = - 2x - 5 ← in slope- intercept form

with slope m = - 2

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - , hence

y = x + c ← is the partial equation of the perpendicular line

To find c substitute (- 1, - 2) into the partial equation

- 2 = - + c ⇒ c = -

y = x - ← equation in slope- intercept form

look in attachments

step-by-step explanation:

a = (-2, 0)

b= (-4, 0)

c = (-5,2)

d = (-1,2)