Provide a matlab code. i dont need a handwritten solution.
the van der pol equation is a model of an electronic circuit that arose back in the days of vacuum tubes: dy dt dt2 1y2 given the initial conditions, y(o)-y(0)-1, solve this equation from t-0 to 10 using the built in ode45 function. display your results as a graph. you will need to reformulate this second order differential equation into a system of two first order equations

∠acb = 8°

step-by-step explanation:

∠xba lies on the circle and is half the measure of the intercepted arc ax

hence

measure of arc ax = 2 × 42° = 84°

∠acb is outside the circle and is

∠acb = (arcab - arcax ), hence

∠acb = 0.5 (100 - 84) = 0.5 × 16° = 8°

4a. is 3 miles every hour

4b. is 1/3 of an hour per mile

step-by-step explanation:

54 kilometers per hour

step-by-step explanation:

according to rules:

1 km = 1000 meter

which means that 1 meter = 1/1000 km

1 hour = 3600 second [ as 1 hour = 60 min = 60 *60 seconds ]

which means that 1 second = 1/3600 hour

therefore, 1 kilometer/hour =

thus to convert 15 meter per second to kilometer per hour, we multiply 15 to 3.6 kilometer/hour.

15 meter/second=   which is the required answer.