Prove that if two circles are tangent externally then the common internal tangent bisects a common external tangent.

Explanation:

Consider the attached diagram.

Circles A and B have mutual tangents CF and DE that intersect at point F.

We know that the two tangents to a circle from an external point are congruent, so ...

  FE≅ FC

  FD ≅ FC

By the transitive property of congruence, both segments congruent to FC are congruent to each other:

  FD ≅ FE

Therefore, CF is a bisector of DE.

required rate of return = 0.166 = 16.6%

step-by-step explanation:

under the capital asset pricing model (capm), the required or expected rate of return for a particular security or asset is given using the formula:

required rate of return = risk-free rate + beta*(market risk premium)

we are given that;

risk-free rate = 4% = 0.04

beta = 1.4

market risk premium = 9% = 0.09

we simply plug these values into the above formula;

required rate of return = 0.04 + 1.4*(0.09)

required rate of return = 0.04 + 0.126

required rate of return = 0.166 = 16.6%

10 - 75

step-by-step explanation:

there's nothing attached so it's most likely anything in that range.