Given a polynomial p(x)=0, which two expressions could be a pair of irrational roots of the equation square root 2-3, 2-square root 3, square root 3-2, 2+ square root 3, -square root 2+3 !

  2-square root 3, 2+ square root 3

Step-by-step explanation:

If the polynomial has rational and real coefficients, the roots will be "conjugates" of each other. That is, the sum of the root should be a rational number. So, the irrational parts will be opposites, while the rational parts remain the same.

  2±√3 . . . can be the roots of p(x) when p(x) has rational real coefficients

the answer is a

step-by-step explanation:

after going and makeing graphs i would go with a,

there is nothing that is matches the graph. if there was i would show you. but therefore my answer is a.

hope i

-lavira: )