this is solving quadratic equations
just the bottom question not the top

  " x = ;  0 " .

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Or;  write in "decimal form" ;  as:  

" x = 0.4 ;  0 " .

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Step-by-step explanation:

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Given:  

10x²  -  4x  =  0  ;  Solve for "x" .

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Factor out a "2x" from the "left-hand side" of the equation:

2x (5x - 2) = 0 ;

Note that "any value";  multiplied by "0" ;  equals "0" ;

We have 2 (two) expressions:

   1)  "  2x " ;  And:

   2)  " (5x - 2) "  ;

→ which, when multiplied together, equal "0" ;

So, set "each" of the 2 (two) expressions "equal to 0 " ;

           and solve for "x" ;

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  1)   " 2x  =  0 " ;  solve for "x" ;

Divide each side of the equation by:  "2" ;  

   to isolate "x" on one side of the equation;

   & to solve for "x" ;

             →   2x/2 = 0/2  ;

             →     x = 0 ;

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  2)   " 5x - 2 = 0 " ;   solve for "x" ;

Add "2" to each side of the equation :    

         5x - 2 + 2 = 0 + 2 ;      

to get:   5x = 2 ;

Now ; divide each side of the equation by:  "5" ;

   to isolate "x" on one side of the equation;

   & to solve for "x" ;

            5x/5 = 2/5 ;

to get:

          x = 2/5 ;

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The answer is:  " x =  ;  0 . "

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 Or;  write in "decimal form" ;  as:  

          " x = 0.4 ; 0 " .

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Hope this is helpful to you!  

    Best wishes!

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the image of (6, 9) under a dilation is (4, 6). the scale factor is