If \cot \theta =\sqrt{3}cotθ= 3 and the reference angle of \thetaθ is 30^\circ30 ∘ , find both angles in degrees from 0^\circ\le \theta < 360^{\circ}0 ∘ ≤θ< 360 ∘ and both angles in radians from 0 \le \theta < 2\pi.0≤θ< 2π.

answer: (1,3) and (-2,0) i think.

the equivalent expression are always the hardest ones but you look at the gcf also

step-by-step explanation:

the answer is c just got it on ed

step-by-step explanation:

the second option

step-by-step explanation: