Kevin operates a movie theater that sells about 800 tickets per day for $8 each. kevin predicts that for each $0.50 increase in the ticket price, 40 fewer tickets will be sold. let x represent the number of $0.50 price increases and f(x) represent the total earnings from ticket sales.
f(x)=-20x^2+80x+6400
kevin wants to determine the best potential earnings from ticket sales each day.
complete the following statement for this situation.
the function reveals that the (minimum or maximum) earnings from ticket sales will be (320,6400,6480 or 720$) after(6,8,4 or 2) $0.50 price increases.

The function reveals that the maximum earning from ticket sales will be $6480 after 2 ($0.50) price increases

Step-by-step explanation:

* Lets explain how to solve the problem

- The function f(x) = -20x² + 80x + 6400 represents the total

 earnings from ticket sales and x represents the number of $0.50

 price increases

∵ f(x) is a quadratic function

∵ The coefficient of x² is -20

∴ The function has a maximum value

- The vertex of the quadratic function f(x) = ax² + bx + c is (h , k),

 where h = -b/2a and k = f(h)

* Lets find the maximum point of f(x)

∵ a = -20 , b = 80

∵ h = -b/2a

∴ h = -(80)/2(-20) = -80/-40 = 2

∵ k = f(h) and h = 2

∴ f(2) = -20(2)² + 80 (2) + 6400

∴ f(2) = -80 + 160 + 6400

∴ f(2) = 6480

∴ k = 6480

* The function reveals that the maximum earning from ticket sales

  will be $6480 after 2 ($0.50) price increases

the answer is d. (1.2, -4.7) on edgn

hope this !

answer: 42

use a calculator to find that 845/73 = 11.575

the whole part of the answer is 11. multiply this by 73 to get 11*73 = 803.

subtract that result from 845 to get 845 - 803 = 42