Find the equation of a line given the point and slope below. arrange your answer in the form y = mx + b, where b is the constant.
(7, 1)
m = 10
can someone me and show me how to do these the following lessons are all on this so tyy owo

Step-by-step explanation:

an equation is :  y = 10x+b

calculate b : this line passes by : (7;1) when x =7  y = 1

so : 10(7)+ b=1

b= -69

so : y = 10x-69

y = 10x - 69.

Step-by-step explanation:

Start with the slope-intercept equation of a straight line, y = mx + b.  We substitute 1 for y, 7 for x, and 10 for m, obtaining:

1 = 10(7) + b

Subtracting 70 from both sides, we get -69 = b.

Thus, the desired equation is y = 10x - 69.

y = 5x + 17

step-by-step explanation:

a perpendicular line will be the opposite reciprocal slope of the given equation.   the slope given is -1/5 so the opposite reciprocal is 5

find b:

7 = 5 (-2) + b

7 = -10 + b

17 = b

write equation

y = 5x + 17

their is no graph showing

step-by-step explanation: