What is the equation of the circle with center (0, 0) that passes through the point (–4, –6)?

If the center is in point P(a,b) and has a radius r then circle equation is:

(x-a)²+(y-b)²=r².

In your task we've got P(0,0) so the circle equation is x²+y²=r².

We have to find r. Radius start at (0,0) and end at (-4,-6) therefore

r=√((-4)²+(-6)²) and

r²=(-4)²+(-6)²=16+36=52.

So answer is x²+y²=52.

what do you mean by fog

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !