The metropolitan bus company claims that the mean waiting time for a bus during rush hour is less than 5 minutes. a random sample of 20 waiting times has a mean of 3.7 minutes with a standard deviation of 2.1 minutes. at α = 0.01, test the bus company’s claim. assume the distribution is normally distributed. state the sample mean and the standard deviation

Decision is reject the as There is sufficient evidence to support the claim that the mean time is less then 5 minutes.

Step-by-step explanation:

Consider the provided information.

The mean waiting time for a bus during rush hour is less than 5 minutes.

Thus the null hypothesis is:

A random sample of 20 waiting times has a mean of 3.7 minutes with a standard deviation of 2.1 minutes. At α = 0.01,

Now use the table to find the z value, where α = 0.01,

The value of n is 20, sample mean is 3.7, population mean is 5 and standard deviation is 2.1.

Now, use the formula: Standardized test statistic for z-scores =.

Substitute the respective values in the above formula.

As, the test statistic is in the reject interval, so reject

There is sufficient evidence to support the claim that the mean time is less then 5 minutes.

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation:

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.