Use the normal distribution of fish lengths for which the mean is 9 inches and the standard deviation is 2 inches. assume the variable x is normally distributed. (a) what percent of the fish are longer than 14 inches? (b) if 300 fish are randomly selected, about how many would you expect to be shorter than 8 inches?

Step-by-step explanation:

Given that fish length X is having the normal distribution  for which the mean is 9 inches and the standard deviation is 2 inches.

X : N(9,2)

A)

B) Here sample size = 300

Out of 300 fish we can expect 300(0.3085) to be shorter

i.e. 92.55=93 fish

hreryryrranswer:

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116