Aright triangle has the length of one of the legs equal to 8cm, and the sine of the angle, opposite to that leg equal 0.8. what are the lengths of the other leg and hypotenuse of that triangle?

Part 1) The length of the hypotenuse is 10 cm

Part 2)The length of the other leg is 6 cm

Step-by-step explanation:

step 1

Find the length of the hypotenuse

Let

x -----> the length of the other leg

y -----> the length of the hypotenuse

A -----> the angle opposite to the leg equal to 8 cm

we know that

we have

substitute

Solve for y

therefore

The length of the hypotenuse is 10 cm

step 2

Find the length of the other leg

Let

x -----> the length of the other leg

y -----> the length of the hypotenuse

we know that

Applying the Pythagoras Theorem

we have

substitute and solve for x

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step-by-step explanation:

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step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]