Asimple random sample of 800 individuals provides 100 yes responses. a. what is the point estimate of the proportion of the population that would provide yes responses (to 2 decimals)? b. what is your estimate of the standard error of the proportion (to 4 decimals)? c. compute the 95% confidence interval for the population proportion (to 4 decimals). ( , )

a) 0.13

b)

Step-by-step explanation:

The confidence interval for population proportion is given by :-

Given : Sample size : n= 800

Number of individuals provides Yes responses =  100

a) The proportion of  individuals provides Yes responses =

hence, the the point estimate of the proportion of the population that would provide Yes responses :

Significance level :

Critical value :

Now, the 90% two-sided confidence interval on the proportion of people who regularly have a dental checkup will be :-

the amount you'd have after the work is $1.55

step-by-step explanation:

you subtract 95% from $31.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

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