Ahigh school class consists of 7 seniors, 10 juniors, 12 sophomores, and 11 freshmen. exactly 4 of the juniors are female, and exactly 2 of the sophomores are male. if two students are randomly selected from this class, what is the probability that the pair consists of a male junior and a female sophomore?

1/13

Step-by-step explanation:

There exactly 7 seniors 10 Juniors, 12 sophomores and 11 freshman

in which 4 of the juniors are Female , and exactly 2 of the sophomores are male. Therefore,

10-4= 6 juniors are male

12-2 = 10 female sophomores

Total = 7+10+12+11= 40 students

P(male junior then female soph.)=

P(female soph then male junior)=

Therefore the final answer will be = 1/26 +1/26= 1/13

answer:  

step-by-step explanation:

here x represents the height of the pole,

and, the height of the shadow of the pole is 12 feet.

also, the angle of elevation from the top of the pole is 40°,

therefore,

by the low of sine,

which is the required equation for finding the value of x,

step-by-step explanation:

the options are kind of confusing. i can tell you what i see going on here when i look at the graph.

the class and exam medians are closely related, and it looks like the low outlier on the exam did pull the median lower. [tex][/tex]