The circus is coming to town. cindy is selling tickets. the first day she sold 8 adult tickets and 5 children tickets for a total of 180.50 in sales. the second day she received $261.00 for 12 adult tickets and 6 children tickets. what is the price of adult tickets? and what is the price of child tickets? write two algebraic equations that model the circus ticket scenario. the problem need to be shown how it is solved by using the elimination method or substitution method

hi there! my name is zalgo and i am here to you out today. the answer is pretty simple (in a way). this equation equals to 25.2!

i hope this answer !

"stay and stay proud! " - zalgo

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116