An urn contains six blue balls and seven yellow balls. if four balls are selected randomly without being replaced, what is the probability that of the balls selected, three of them will be blue and one of them will be yellow?

0.0490

Step-by-step explanation:

Given : Number of blue balls = 6

Number of yellow balls = 7

Total number of balls = 13

Total number of ways for selecting 4 balls from 13 balls :-

The number of ways of selecting 3 blue and one yellow :-

Now, the probability that of the balls selected, three of them will be blue and one of them will be yellow :-

Hence, the required probability is 0.0490 .

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5