Me !
a player gets to throw 4 darts at the target shown. assuming the player will always hit the target, the probability of hitting an odd number three times is times more than the probability of hitting an even number three times.

The probability of hitting an odd number three times is 3.375 times more than the probability of hitting an even number three times..

Step-by-step explanation:

Probability of hitting an odd number = 3/5

Probability of hitting an odd number = 2/5

Probability of hitting an odd number three times = (3/5)^3

Probability of hitting an odd number three times = (2/5)^3

Now divide (3/5)^3 by  (2/5)^3 we get:

(3/5)^3 / (2/5)^3

(3)^3/(2)^3

27/8 = 3.375

The probability of hitting an odd number three times is 3.375 times more than the probability of hitting an even number three times..

i dont know and i dont care for math bc it is a stupied subject

step-by-step explanation:

eww xbox also eww dayz

step-by-step explanation:

just for that im not answering