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Mathematics, 02.08.2019 18:20 asuhdude57

In a study of cell phone usage and brain hemispheric dominance, an internet survey was e-mailed to 6999 subjects randomly selected from an online group involved with ears. there were 1301 surveys returned. use a 0.01 significance level to test the claim that the return rate is less than 20%. use the p-value method and use the normal distribution as an approximation to the binomial distribution. identify the null hypothesis and alternative hypothesis. a. upper h 0: pequals0.2 upper h 1: pless than0.2 your answer is correct. b. upper h 0: pgreater than0.2 upper h 1: pequals0.2 c. upper h 0: pequals0.2 upper h 1: pnot equals0.2 d. upper h 0: pless than0.2 upper h 1: pequals0.2 e. upper h 0: pequals0.2 upper h 1: pgreater than0.2 f. upper h 0: pnot equals0.2 upper h 1: pequals0.2 the test statistic is zequals negative 2.95. (round to two decimal places as needed.) the p-value is 0.002. (round to three decimal places as needed.) because the p-value is less than the significance level, reject the null hypothesis. there is sufficient evidence to support the claim that the return rate is less than 20%.

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In a study of cell phone usage and brain hemispheric dominance, an internet survey was e-mailed to 6...
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