Asolid sphere rolls down an inclined plane without slipping. if the center of mass of the sphere has a linear acceleration of 1.21 m/s^2, what is the angle of the incline to the horizontal?

angle of inclination to the horizontal is 9.95°

Step-by-step explanation:

Let the angle of inclination be θ

We know acceleration , a = 1.21 m/

Now using effective mass concept, we get

Therefore, solving for θ, we get

θ = 9.95°

Therefore, angle of inclination to the horizontal is 9.95°

0

step-by-step explanation:

you can not divide by 0 so 4 ÷ 0 would be 0

0 × 9999 =0

mark brainliest   : )