There are two college entrance exams that are often taken by students, exam a and exam b. the composite score on exam a is approximately normally distributed with mean 21.5 and standard deviation 5. the composite score on exam b is approximately normally distributed with mean 1025 and standard deviation 214. suppose you scored 23 on exam a and 1231 on exam b. which exam did you score better on? justify your reasoning using the normal model.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

b i think

step-by-step explanation:

not really sure

the answer would be c:   ax + b = ax + c

step-by-step explanation:

$9.89

step-by-step explanation:

9.90 = p x .06 x .25 (3/12 changed to a decimal)

9.90 = p x 0.015

9.90 - 0.015 = p

9.89 = p