The function s(v) = describes the side length, in units, of a cube with a volume of v cubic units. jason wants to build a cube with a minimum of 64 cubic centimeters. what is a reasonable range for s, the side length, in centimeters, of jason’s cube?

s≤4 cm.

Step-by-step explanation:

Let s be side of cube.

As we know that the volume of cube=side×side×side

Here, it is given that the volume of cube = 64 cubic centimeters.

or we can write

side×side×side=64 cubic centimeters

Taking cube root both sides

side= 4 cm

In order to build a cube with a minimum of 64 cubic centimeters,

we can take the value of s≤4 cm.

Hence, the reasonable range for s, the side length is s≤4 cm.

if gloria has "carry over" minutes, (that is, any minutes paid for but not used in a month can be applied to her payment for minutes in the next month,) her total usage for the three months is: total minutes = 320 + 243 + 489 = 1052 minutes number of 200 minute blocks = 1052/200 = 5 r52 (that is 5 with a remainder of 52) rounding up the number of 200 minute blocks gives her usage for the three months as 6 blocks. the cost for six blocks is 6 x $25 = $150 she also has 200 - 52 or 148 carry over minutes if gloria pays each month and unused minutes are lost, applying the rounding up procedure to each month gives: first month usage of 320 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 second month usage of 243 minutes rounds up to 2 blocks of 200 minutes for a payment of 2 x $25 = $50 third month usage of 489 minutes rounds up to 3 blocks of 200 minutes for a payment of 3 x $25 = $75 total payments for the three months are $50 + $50 + $75 = $175 get the plan with carry over minutes!