Worth lots of extra points + a friend if you answer two stoves were turned off at the same time, and they both started to cool down. the following equation gives the temperature of the first stove (in degrees celsius) as a function of time (in minutes) t= 180 - 1.55m the graph of the temperature of the second stove (in degrees celsius) as a function of time (in minutes) is shown below. which stove started at a higher temperature? a. first stove b. second stove c. the stove started at the same temperature which stove cooled down at a greater rate? a. first stove b. second stove c. the stoves cooled done at same rate

B for both

Step-by-step explanation:

The answer is B for both questions. I know this because it's a Khan Academy question and I solved it to help ya out :)

B

Step-by-step explanation:

i think the answer is b)

step-by-step explanation:

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below: