Aparticular species of salmon has an average weight of 57 lb, with a standard deviation of 6.3 lbs. researchers studying salmon in a particular river find that in a sample of 45 fish, average weight is 60.2 lbs. what should researchers do?
a. reject the null hypothesis; these fish are not larger than usual
b. do not reject the null hypothesis; these fish are larger than usual
c. do not reject the null hypothesis; these fish are not larger than usual
d. reject the null hypothesis; these fish are larger than usual

Step-by-step explanation:

Given:

population mean, mu = 57 lb

population standard deviation, sigma = 6.3 lb

Sample mean, x = 60.2 lb

Sample size, n= 45

Null hypothesis x = mu  (i.e. sample mean is not greater than usual, using a significance level of 0.05)

Here we have a case where population mean and standard deviation are known (given).

We calculate the z-score

z=(x-mu)/(sigma/sqrt(n))  

= (60.2-57)/(6.3/sqrt(45))

= 3.41

P(x>mu) = P(z>3.41) = 0.99968  >> 0.95  (one sided tail)

Therefore we can reject the null hypothesis and accept the alternate hypothesis that fish are larger than usual.

so what is the problem what are they asking you to solve

step-by-step explanation:

so what is the problem what are they asking you to solve

step by step solution :

step   1   :

1.1     4 = 22

(4)3 = (22)3 = 26

equation at the end of step   1   :

  ((23) • 26)2

step   2   :

equation at the end of step   2   :

  (23 • 26)2

step   3   :

final result :

  218

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