Two six sided dice are rolled. what is the probability of one of the dice being a 4?
a. 11/36 or 33%
b. 1/4 or 25%
c. 1/6 or 17%
d. 1/3 or 33%

Step-by-step explanation:

There is a long way to do this. There are 36 ways that 2 dice can be rolled.

1   5

5  1

The top die is equilly likely to roll as the bottom combination. In all you have 6*6 ways that 2 dice can fall. How many ways have exactly 1 four.

4  1

4  2

4  3

4  5

4  6

Where did 4 4 go? Why wasn't it included. It wasn't included because there are 2 fours, not just one.

Is that all you can get? No. The second die would give exactly the same thing.

1   4

2  4

3  4

5  4

6  4

That's 10 ways altogether. The total number of ways of throwing 2 dice and accepting anything is 36.

The probability of  throwing a 4 on one of them is 10/36 = 5/18 = 0.2777778

  a.  11/36 or 33%

Step-by-step explanation:

Possible outcomes in which one of the dice is a 4 are ...

  (1, 4), (2, 4), (3, 4), (4, 4), (5, 4), (6, 4), (4, 1), (4, 2), (4, 3), (4, 5), (4, 6)

There are 11 of them, including the case where both dice are 4. Since there are 36 possible outcomes, the probability of one die being 4 is 11/36.

The probability of "exactly one" die being a 4 is 10/36 = 5/18, not an answer choice. Hence we assume the above interpretation of the question is the correct one.

well what you have to do is divide 84 by 6 so theanswer

step-by-step explanation:

84 divided by 6 = 14

and that lightbulb changing party must be freaking lit!

probably .5

i can on others if necessary.